2x^2+6x-3.5=0

Solution for 2x^2+6x-3.5=0 equation:

2x^2+6x-3.5=0

a = 2; b = 6; c = -3.5;
Δ = b2-4ac
Δ = 62-4·2·(-3.5)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-8}{2*2}=\frac{-14}{4}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+8}{2*2}=\frac{2}{4}
=1/2
$